3m^2-60m-99=0

Solution for 3m^2-60m-99=0 equation:

3m^2-60m-99=0

a = 3; b = -60; c = -99;
Δ = b2-4ac
Δ = -602-4·3·(-99)
Δ = 4788
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4788}=\sqrt{36*133}=\sqrt{36}*\sqrt{133}=6\sqrt{133}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-6\sqrt{133}}{2*3}=\frac{60-6\sqrt{133}}{6}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+6\sqrt{133}}{2*3}=\frac{60+6\sqrt{133}}{6}
$